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artcher [175]
4 years ago
15

Read the following conjecture.

Mathematics
2 answers:
Mars2501 [29]4 years ago
4 0
48 is not a multiple of 9 at all and that might be the problem sorry dont really understand it.
uranmaximum [27]4 years ago
3 0

Answer:

45

Step-by-step explanation:

We have to prove that any number that is divisible by 3 need not be divisible by 9

To show that conjecture that any number that is divisible by 3 is also divisible by 9 we have to show an counter example.

THe four options given are 18, 27, 48 and 45.

Out of these 4 numbers, 18, 27, 45 are divisible by both 3 and 9.

Hence these numbers cannot be shown as counter example.

Take the case of 48

48 is divisible by 3 as 48 =16(3)

But 48 is not divisible by 9.

Thus 45 is a good counterexample to prove number that is divisible by 3 is also divisible by 9 is false.

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