6x+4y=12 into y=my+b

2 answers:

7 0

6x + 4y = 12...subtract 6x from both sides
4y = -6x + 12 ...divide both sides by 4
(4/4)y = (-6/4)x + 12/4...reduce
y = -3/2x + 4 <== y = mx + b

igor_vitrenko [27]3 years ago

4 0

No . 6x+4y=12 in linear equation form is
y= -3/2x + 3 not 4 because 12 divided by 4 is 3.

You might be interested in

(b) Three objects are brought close to each other, two at a time. When objects A and B are brought together, they repel. When ob

zheka24 [161]

Answer:

Step-by-step explanation:

When A and B are brought together then they repel i.e. A and B have same charge, either negative or positive

When B and C are brought together then they also repel. This implies that nature of charge on B and C is same

4 0

3 years ago

How do you evaluate the expression to this problem 24 divided by (-4)+(-2) times (-5)

Tju [1.3M]

24/-30 would be the answer

8 0

3 years ago

Read 2 more answers

single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec

givi [52]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

a) Rolling an Odd number in first throw

A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

Total Favorable outcomes (Odd numbers) = 3

Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = $\frac{3}{6} = \frac{1}{2}$

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

So,

The probability of rolling a number greater than 3 = $\frac{3}{6} = \frac{1}{2}$

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$