For which of these functions does the function value change at a constant rate per unit change in x? Explain.
1 answer:
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AC=x, BC=x√3, AB is a hypotenuse (look at the pic below)
x√3>x, consequently ∠B<∠A and we have to find cosB, which is (x√3)/AB.
<em>Let's find AB:</em>
AB=√(x²+(x√3)²)=√(x²+3x²)=√(4x²)=2x
<em>Thus, cosB is:</em>
cosB=(x√3)/(2x)=√3/2
x√3>x, consequently ∠B<∠A and we have to find cosB, which is (x√3)/AB.
<em>Let's find AB:</em>
AB=√(x²+(x√3)²)=√(x²+3x²)=√(4x²)=2x
<em>Thus, cosB is:</em>
cosB=(x√3)/(2x)=√3/2
Answer:
height = 142.00 ft
height ≈ 200. 82 ft
height ≈ 245.95 ft
Step-by-step explanation:
The picture below represent the image of the draw bridge. The illustration will form a right angle triangle. The hypotenuse is each half of the drawbridge which is 284 ft long. The opposite side of the triangle is facing the drawbridge half leg and the adjacent side is horizontal length. This is the side that made the angle with the drawbridge half leg(hypotenuse).
The question ask us to find the height of the drawbridge when it rise which is the opposite sides of the triangle when the angle is 30° , 45° and 60°.
Using SOHCAHTOA principle,
Angle 30°
sin 30° = opposite/hypotenuse
sin 30° = height/284
cross multiply
height = 0.5 × 284
height = 142.00 ft
Angle 45°
sin 45° = height/284
height = 284 × 0.70710678118
height = 200.818325857
height ≈ 200. 82 ft
Angle 60°
sin 60 = height/284
cross multiply
height = 0.86602540378 × 284
height = 245.951214675
height ≈ 245.95 ft
