Since secant is the inverse of cosine function, when the cosine function has a 'zero' the secant will have a vertical asymptote.
Graphing a cosine with a right shift of pi, the zeros would be at pi and 2pi.
This will make the vertical asymptotes of the secant function be at pi and 2pi.
I hope you understand.
0x1=0
1x2=2
2x3=6
3x4=12
4x5=20
Answer:
1. x<3
2. x<3
Step-by-step explanation:
2x-5<1
Move constant to the right side and change its sign
2x<1+5
Add the Numbers
2x<6
Divide both sides of the inequality by 2
x<3
3x+7<16
Move constant to the right side and change its sign
3x<16-7
Subtract the numbers
3x<9
Divide both sides of the inequality by 3
x<3
<h2>(25) 7th Grade Swimmers</h2><h2>25:80</h2>
Answer:
I would say C or D but im goin' with C
Step-by-step explanation:
I hope this helps.