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Citrus2011 [14]
3 years ago
13

Classify 4x^5+2x^4-5x^3+12 by number of terms

Mathematics
2 answers:
Semenov [28]3 years ago
7 0
That is 4 terms long. 
natali 33 [55]3 years ago
4 0
It is 4 terms long

Hope this helps
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Indica si cada afirmación es verdadero (v) o falso (f) .
Ksivusya [100]

<span>A es falso porque podría dividirse por negativo.

B es verdadero porque el divisor siempre entrará en el dividendo.

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D es falso porque la propiedad asociativa no se aplica a la división.

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PLEASE HELP!!! A bridge has a weight limit of 5000 kg. What is the heaviest load that a pickup truck weighing 4500 pounds could
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Step-by-step explanation:

The load limit of the bridge is ...

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2 years ago
Andrea, Justin, and Virginia went to an office supply store. Andrea bought 6 pencils, 7 markers, and 8 erasers. Her total was $1
olga2289 [7]

Answer:

x=0.25\,,\,y=1.75\,,\,z=0.25

Step-by-step explanation:

Let x,y,z denotes number of pencils, markers, erasers respectively.

For Andrea:

6x+7y+8z=15.75\,\,\,(i)

For Justin:

6x+8y+5z=16.75\,\,\,(ii)

For Virginia:

5x+5y+7z=11.75\,\,\,(iii)

On subtracting equations (i) and (ii), we get

(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z

Put y=1+3z in equation (i)

6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)

Put y=1+3z in equation (iii)

5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25

Put z=0.25 in equation y=1+3z

y=1+3(0.25)=1.75

Put y=1.75\,,\,z=0.25 in equation (i)

6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25

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