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3 years ago

Solve the system algebraically.

Mathematics

2 answers:

Sonja [21]3 years ago

8 0

Answer:

5 is the value of y

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polet [3.4K]3 years ago

5 0

The value of y is 5

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Where is the center of the largest circle that you could draw inside a given triangle? . A.the point of concurrency of the media

juin [17]

The correct answer is:

C.the point of concurrency of the angle bisectors of the triangle

Explanation:

The largest circle that can be drawn inside a triangle is called an inscribed circle. The center of this circle is called the incenter.

The incenter is formed by the intersection of the angle bisectors of all 3 angles in the triangle.

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3 years ago

Read 2 more answers

In the figure below, if angle D measures 43 degrees, what is the measure of angle A?

Zielflug [23.3K]

Sorry where is the figure.. oiii figure where

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4 years ago

After buying five coloring books that cost $3 each, Mary had %8.50 left. How much money did she have at first

TiliK225 [7]

Answer:

$23.50

Step-by-step explanation:

$8.50 + $3(5) = $23.50

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3 years ago

If a hurricane was headed your way, would you evacuate? The headline of a press release issued January 21, 2009 by the survey re

Nikolay [14]

Answer:

The 98% confidence interval for population proportion of people who refuse evacuation is {0.30, 0.33].

Step-by-step explanation:

The sample drawn is of size, n = 5046.

As the sample size is large, i.e. n > 30, according to the Central limit theorem the sampling distribution of sample proportion will be normally distributed with mean $\hat p$ and standard deviation $\sqrt{\frac{\hat p (1-\hat p)}{n} }$ .

The mean is: $\hat p=0.31$

The confidence level (CL) = 98%

The confidence interval for single proportion is:

$CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]$

Here $z_{(\alpha /2)}$ = critical value and α = significance level.

Compute the value of α as follows:

$\alpha =1-CL\\=1-0.98\\=0.02$

For α = 0.02 the critical value can be computed from the z table.

Then the value of $z_{(\alpha /2)}$ is ± 2.33.

The 98% confidence interval for population proportion is:

$CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]\\=[0.31-2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} },\ 0.31+2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} } ]\\=[0.31-0.0152,\ 0.31+0.0152]\\=[0.2948,0.3252]\\\approx[0.30,\ 0.33]$

Thus, the 98% confidence interval [0.30, 0.33] implies that there is a 0.98 probability that the population proportion of people who refuse evacuation is between 0.30 and 0.33.

7 0

3 years ago

Determine the center and radius of the following circle equation:

Greeley [361]

Answer:

x^2-18x+y^2+18y+137=0

express both x and y term in completed square form

(x-9)^2 -81+(y+9)^2-81+137=0

(x-9)^2+(y+9)^2-25=0

(x-9)^2+(y+9)^2=5^2

here the x coordinate of the centre is +9

y coordinate is -9(the negative value of the value associated with the x and y square brackets)

radius=5

8 0

3 years ago