Answer:
By AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Here WXY is an isosceles triangle with legs WX & WY
So WX = WY
Hence ∠X = ∠Y
So ∠2= ∠3.
Now by angle sum property
∠1 + ∠2+∠3 = 180°
∠1+∠2+∠2=180°
2∠2 = 180° - ∠1 .......(1)
In triangle WVZ
WV = WZ
So ∠V = ∠Z
∠4 = ∠5
Once again by angle sum property
∠1 + ∠4 + ∠5=180°
∠1 + ∠4 + ∠4 = 180°
2∠4 = 180° - ∠1 ...(2)
From (1) & (2)
2∠2 = 2∠4
∠2=∠4
Now ∠W is common to both triangles
Hence by AA
ΔWXY ~ΔWVZ
Answer:
Lines y = -x+4 and y= 3x+3 intersect the y-axis
Answer:
How to factor out a polynomial with a 3rd degree-• well here is a For example, let G(x) = 7x³ – 125. Then factoring this third degree polynomial relieve on a differences of cubes as follows: (2x – 5) (4x² + 20x + 25), where ²x is the cube-root of 8x³ and 5 is the cube-root of 1256
Answer:
373.8mmHg
Step-by-step explanation:
a =height (in km) above sea level,
the pressure P(a) (in mmHg) is approximated given as
P(a) = 760e–0.13a .
To determine the atmospheric pressure at 5.458 km, then we will input into the equation
P(5.458km) = 760e–0.13a .
= 760e^(-0.13×5.458)
=760e^-(0.70954)
= 760×0.4919
=373.8mmHg
Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg