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love history [14]
3 years ago
6

Use trigonometry to find the missing side. Round your answer to the nearest tenth (one decimal place)

Mathematics
1 answer:
Alchen [17]3 years ago
5 0

Given:

A figure of a right triangle.

To find:

The missing side by using the trigonometric ratios.

Solution:

In a right angle triangle,

\cos \theta=\dfrac{Adjacent}{Hypotenuse}

In triangle ABC,

\cos A=\dfrac{AC}{AB}

\cos (31^\circ)=\dfrac{b}{270}

0.857=\dfrac{b}{270}

Multiply both sides by 270.

0.857\times 270=b

231.39=b

b\approx 231.4

Therefore, the missing side length is b=231.4 inches.

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2x-6y=12 and -5x+15y=-30 elimination
Reptile [31]

Answer:

unsolvable because the second equation is just -2.5 times the first equation.

Step-by-step explanation:

2x-6y=12    then   2x=12+6y     x=6+3y

-5x+15y=-30

substitute x

-5(6+3y)+15y=-30

-30-15y+15y=-30

y=y

8 0
3 years ago
Need help for number 4 please
Marina CMI [18]

Answer:

Step-by-step explanation:

4) ΔSTW ≅ ΔBFN . So, corresponding parts of congruent triangles are congruent.

a) BN = SW                                        d) m∠W = m∠N

  BN = 9 cm                                           m∠W = 82°

b) TW = FN                                        e) m∠B = m∠S

TW = 14 cm                                            m∠B = 67°

c) BF = ST                                          f) m∠B + m∠N + m∠F = 180°

  BF = 17 cm                                                 67 + 82 + m∠F = 180

                                                                            149 + m∠F = 180

                                                                                     m∠F = 180 - 149

                                                                                      m∠F = 31°          

5) ΔUVW ≅ ΔTSR

UV = TS

12x - 7 = 53

   12x   = 53+7

   12x = 60

      x = 60/12

      x = 5

UW =TR

3z +14 = 50

    3z = 50 - 14

   3z = 36

     z = 36/3

    z = 12

SR =VW

5y - 33 = 57

     5y = 57 + 33

     5y = 90

       y = 90/5

       y = 18

7) ΔPHS ≅ ΔCNF

∠C = ∠P

4z - 32 = 36

      4z = 36 + 32

       4z = 68

        z = 68/4

       z = 17

∠H = ∠N

6x - 29 = 115

  6x     = 115 + 29

      6x = 144

        x = 144/6

       x = 24

∠P + ∠H + ∠S = 180   {Angle sum property of triangle}

36 +115 + ∠S = 180

      151   + ∠S = 180

                ∠S = 180 - 151

               ∠S = 29°

∠F = ∠S

3y - 1 = 29

   3y = 29 + 1

  3y = 30

    y = 30/3

    y = 10

8) ΔDEF ≅ ΔJKL

DE = 18    ;  EF = 23

DF = 9x - 23

JL= 7x- 11

DF = JL           {Corresponding parts of congruent triangles}

      9x - 23 = 7x - 11

9x  - 7x - 23 = -11

        2x - 23 = -11

               2x = -11 + 23

               2x = 12

                 x = 12/2

                x = 6      

JK   = DE           {Corresponding parts of congruent triangles}

3y - 21  = 18

       3y = 18 + 21

        3y = 39

         y = 39/3

        y = 13

4 0
3 years ago
I want a way to solve this question​
noname [10]

Answer:

Step-by-step explanation:

cos~L=\frac{m^2+n^2-l^2}{2mn} \\=\frac{5^2+8^2-7^2}{2*5*8} \\=\frac{25+64-49}{80} \\=\frac{40}{80} \\=\frac{1}{2} \\=cos 60\\

∠L=60°

5 0
2 years ago
Pls help me show work too:(
fredd [130]
X=2.5 the triangles are 2x the scale of the other one so if you divide the numbers on the triangle by 2 then you will get the answer for x
4 0
3 years ago
The width of a rectangle is (5x + 2) inches and the length is (6x − 7) inches. Find the area of the rectangle.
Degger [83]

Answer:

<h2><u><em>30x² − 23x − 14</em></u></h2>

Explanation:

  • Area = Length · Width

Length: (6x - 7)

Width: (5x + 2)

  • Create An Equation

(6x - 7) (5x + 2)

= (6x + −7)(5x + 2)

(6x)(5x) + (6x)(2) + (−7)(5x) + (−7)(2)

= 30x² + 12x − 35x − 14

  • 30x² − 23x − 14

- PNW

7 0
3 years ago
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