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taurus [48]
3 years ago
13

What is the y-intercept for the graph of 7x – 3y = –5?

Mathematics
2 answers:
posledela3 years ago
6 0
<span>Slope = -4.667/2.000 = -2.333 
x-intercept = 5/7 = 0.7<span>
y-intercept = 5/3 = 1.7</span></span>
AysviL [449]3 years ago
3 0
2 ways to find the y int.

(1) put the equation in y = mx + b form and the y int will be in the b position
7x - 3y = -5
-3y = -7x - 5
y = 7/3x + 5/3....so 5/3 is ur y int

(2) another way is to sub in 0 for x and solve for y
7(0) - 3y = -5
-3y = -5
y = -5/-3
y = 5/3...ur y int
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Answer:

x=2

Step-by-step explanation:

So we have the equation:

5^x+5^{x+1}=150

First, separate the second term:

5^x+(5\cdot5^x)=150

Let u equal 5ˣ. So:

u+5u=150

Combine like terms:

6u=150

Divide both sides by 6:

u=25

Substitute back u:

5^x=25

Take the base 5 logarithm of both sides:

\log_5(5^x)=\log_5(25)

The left cancels:

x=\log_5(25)

Evaluate the right:

x=2

So, our answer is 2.

And we're done!

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Step-by-step explanation:

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A spool contains 270 inches of wire. How many pieces of wire, each with the a length of 1 7/8 inches, can be cut from the spool?
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Step-by-step explanation:

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Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

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= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
3 years ago
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