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galina1969 [7]
3 years ago
13

Solve a÷b(×)-c=0 for xHelp me please :)

Mathematics
1 answer:
adell [148]3 years ago
3 0
A b x−c=0 Step 1: Multiply both sides by b. ax−bc=0 Step 2: Add bc to both sides. ax−bc+bc=0+bc ax=bc Step 3: Divide both sides by x. ax x = bc x a= bc x Answer: a= bc x
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Determine which of the following formulas hold for all invertible n×n matrices A and B.
garik1379 [7]

Answer:

1 hold

2 hold

3 does not hold

4 hold

5 hold

6 hold

7 does not hold

8 does not hold

9 Does not hold

10 Hold

Step-by-step explanation:

The detailed step by step verification is as shown in the attachment

4 0
3 years ago
The points , (−15,1) and , (−7,r) lie on a line with slope 5/4. Find the missing coordinate r. Click image to enlarge
Nadya [2.5K]

The missing coordinate r is 11.

Solution:

Given points are (–15, 1) and (–7, r).

x_{1}=-15, x_{2}=-7, y_{1}=1 \text { and } y_{2}=7

Slope (m) = \frac{5}{4}

<u>To find the missing coordinate r:</u>

Slope formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute the given values in the formula.

$\frac{5}{4}=\frac{r-1}{-7-(-15)}

$\frac{5}{4}=\frac{r-1}{-7+15}

$\frac{5}{4}=\frac{r-1}{8}

Do cross multiplication.

8 \times 5=4(r-1)

40 = 4r – 4

Add 4 on both side of the equation.

44 = 4r

Divide by 4 on both side of the equation.

11 = r

⇒ r = 11

Hence the missing coordinate r is 11.

6 0
3 years ago
In designing a true/false test you use a random number generator to determine if the answer is true or false. This gives you a r
yan [13]

Answer:

no because

Step-by-step explanation:

the results were not tested enough

5 0
3 years ago
A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da
allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation S'(t)= -30t^{2} + 420t. The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\  S(t)= -10t^{3} +210t^{2} \\

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

Given\ S(t) = -10t^{3} + 210t^{2}

S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

8 0
3 years ago
Solving Systems by Substitution
kenny6666 [7]

Answer:

hope it will help you ....

7 0
2 years ago
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