Answer: i think it’s distributive don’t kill me if it’s wrong
Step-by-step explanation:
Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
The 5-d process is the process in answering problems with things meaning
if you have amanda is x and jake is 3 times amandas age....and there mother is 4 times jakes age..and there sum of ages is ....its these kind of problems. so you have a step by step process to solve them...(but you can do it without and skip a few steps when doing it )
but here it is-->
1) describle or draw the problem
2) Define (define what varables you are using
3) Do (Set up equation and solve)
4)Decide (chekc ur answer)
5)Declare ( write the final answer (ex..amanda is 2, Jake is 6...)
hope this helps
