Answer:
Step-by-step explanation:
Given
ID Card of 5 digits
Possibly Digits = {0,1...,9}
Required
Probability that a card has exact number 94213
First, we have o determine the total possible number of ID card numbers
Let the card number be represented by ABCDE
Given that repetition of digits is not allowed;
<em>A can be any of 10 digits</em>
<em>B can any of the remaining 9 digits</em>
<em>C can be any of the remaining 8 digits</em>
<em>D can be any of the remaining 7 digits</em>
<em>E can be any of the remaining 6 digits</em>
<em />
Total number of cards = 10 * 9 *8 * 7 * 6
Total = 30240
Provided that the card number is generated at random; each card number has the same probability of
Hence, the probability of having 94213 is
Answer:
Step-by-step explanation:
This is permutation, since order matters. The formula for us is
₁₈P₅ = 
which simplifies to
₁₈P₅ = 
The factorial of 13 cancels out on the top and bottom leaving you with
₁₈P₅ = 18 × 17 × 16 × 15 × 14
which comes to 1,028,160 ways
Another way to look at it is: the first 5 people of 18 finish and the others you don't care about. Once the first place person is first, there are only 4 of the 18 left to finish in second place. Then there are only 3 left to finish in third place, etc. So if we use that reasoning, we don't even need to use the formula, we can just say
18 * 17 * 16 * 15 * 14 and those are the first 5 people of 18 to finish.
1. 259
2. 80
3. 5316
4. 5
5. 2524
You can just simplify to make an equivalent equation:
(2)(3x + 8) = 5 ⇒ 6x + 16 = 5
Answer:
Hope it helped,
BioTeacher101
<em>(If you have any questions feel free to ask them in the comments)</em>
Solve for x by simplifying both sides of the equation, then isolating the variable.
x = 4
