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3 years ago

Six times a number is greater than 20 more than that number. What are the possible values of that number?

Mathematics

2 answers:

notsponge [240]3 years ago

8 0

b. n>4 its the answer so it shouldn't be wrong

svetlana [45]3 years ago

5 0

Answer: The correct option is (b) n > 4.

Step-by-step explanation: Given that six times a number is greater than 20 more than that number.

We are to find the possible values of the number.

Let the given number be n.

Then, according to the given information, we have

$6\times n>n+20\\\\\Rightarrow 6n>n+20\\\\\Rightarrow 6n-n>20\\\\\Rightarrow 5n>20\\\\\Rightarrow n>\dfrac{20}{5}\\\\\Rightarrow n>4.$

Thus, the required possible values of the number are given by

n > 4.

Option (b) is CORRECT.

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We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
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$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

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In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

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$\lim_{t \to 14.75^{-}} f(t) = 66$ .
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$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

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