First, given graph is very inaccurate. I suppose that you made net with pen.
a) The slope is the angle ( tan∡) between your graph and x axis.
The slope represent the level of the earnings growth.
b) According to the given graph y-intercept= 30$
Y-intercept represent starting amount of money.
c) If we accept that y=70 is connected with x=2 and y=30 with x=0
The slope is S= (70-30)/2= 40/2=20
Linear equation for this function is
y= 20x+30
d) When we replace y=300$ in the equation we get
20x+30=300 => 20x=300-30 => 20x=270 => x=270/20=13.5h
x=13.5h
Good luck!!!
Answer:
The range is y ≥ -1
Step-by-step explanation:
∵ f(x) = (x - 4)(x - 2)
∴ f(x) = x² - 2x - 4x + 8
∴ f(x) = x² - 6x + 8 ⇒ quadratic function (ax² + bx + c) represented by
parabola graphically
∵ a = 1 , b = -6 , c = 8
∴ x-coordinate of its vertex = -b/2a = -(-6)/2×1 = 3
∴ f(3) = (3)² - 6(3) + 8 = -1
∵ a is positive ⇒ the curve has minimum point and it's open upward
∴ the minimum point is (3 , -1)
∴ The range is y ≥ -1 ⇒ because the minimum value is -1
Answer:
he minimum size of a standard parking space shall be nine feet wide and eighteen feet long. Parking spaces within enclosed garages shall have an interior dimension of at least ten feet wide and twenty feet long. The minimum size of a compact parking space shall be eight feet wide and sixteen feet long.
Step-by-step explanation:
Let's work on the left side first. And remember that
the<u> tangent</u> is the same as <u>sin/cos</u>.
sin(a) cos(a) tan(a)
Substitute for the tangent:
[ sin(a) cos(a) ] [ sin(a)/cos(a) ]
Cancel the cos(a) from the top and bottom, and you're left with
[ sin(a) ] . . . . . [ sin(a) ] which is [ <u>sin²(a)</u> ] That's the <u>left side</u>.
Now, work on the right side:
[ 1 - cos(a) ] [ 1 + cos(a) ]
Multiply that all out, using FOIL:
[ 1 + cos(a) - cos(a) - cos²(a) ]
= [ <u>1 - cos²(a)</u> ] That's the <u>right side</u>.
Do you remember that for any angle, sin²(b) + cos²(b) = 1 ?
Subtract cos²(b) from each side, and you have sin²(b) = 1 - cos²(b) for any angle.
So, on the <u>right side</u>, you could write [ <u>sin²(a)</u> ] .
Now look back about 9 lines, and compare that to the result we got for the <u>left side</u> .
They look quite similar. In fact, they're identical. And so the identity is proven.
Whew !
31.75 as an improper fraction is 127/4. The mixed number fraction is 31 3/4.
