Answer:
Inez worked for 2 hours 32 minutes more than Joe
Step-by-step explanation:
Here, we are to calculate the difference in the amount of time in which both of them spent working.
Mathematically, that would be the time spent by Inez minus the time spent by Joe
= 7 hrs 23 minutes - 4 hrs 51 minutes
This works like normal arithmetic subtraction;
Since we cannot subtract 51 minutes from 23 minutes, we need to borrow 1 hour ( 60 minutes) from 7 , and it becomes 6 while our minutes become (60 + 23 = 83 minutes).
So the difference here will be (6-4)hrs and (83-51) minutes = 2 hrs 32 minutes
there were 145 boys on the honor role and 60 girls equally given a total number of 205. This year, the number of boys decreased by 20% = 0.2*145=29
145-29=116
116 is this year number of boys on honor role
For girls.
=0.25*60=15
60-15=45
45 is this year number of girls on honor role.
Total number of students on honor role this year is 116+45 =161
Percentage of decrease = 1 -(161/205)*100% =( 1-0.785)*100
= 0.215*100
= 21.5%
Step-by-step explanation:
2/4(9) + 8
2/36 +8
using l.c.m
2+36(8)
__________
36
2+288=290/36 =8.1
Answer:
Step-by-step explanation:
5
Answer:
1 sig figs = 1st number is a non zero number and all following numbers are zero (if no decimal point present)
if decimal point is present then it can be 0.x where the x can be any number but nothing can come after it
Step-by-step explanation:
