Hello there!
The correct answers are:
A. Mammals
B. Birds
D. Reptiles.
Hope This Helps You!
Good Luck :)
This can be solved either by using a Punnet Square or you can use the formula (n(n+1))/2, where n is the number of alleles. However, using either method will give you the number of possible genotypes regardless if it's homozygous or heterozygous. If we use the second formula, that will give you 10 possible genotypes. Since you only want to know the number of heterozygous genotypes, you should subtract the number of possible homozygous genotypes. In this case, there are four. That is (A1,A1), (A2,A2), (A3,A3), and (A4,A4). Knowing this, you'd be able to figure out that there are six heterozygous genotypes.
(A1,A2), (A2,A3), (A3,A4), (A1,A4), (A1,A3), (A2,A4)
The mass number is the sum of the number of protons and number of neutrons the atom has.
So, we can write the equation as:
x + 20 = 40
x = 20 neutrons.
Answer:
Explanation:
Both parents have black color and normal vision but some of their progenies show brown color and some shows PRA, this reveals the brown coat color and PRA are recessive traits and both parents are heterozygous. The progenies include black normal vision, brown normal vision and black, PRA, that is the alleles for these genes separate independently of each other.
Let us denote the alleles as B-black, b-brown and P-normal vision, p-PRA, then the genotype of the heterozygous parent is BbPp, alleles separate independently of each other so the possible gametes are alleles for the color and vision segregate independently during gamete formation.
Thus, option C is correct.