Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
The midsegments the triangle have is three
The expression of the height is

the index "n" is the numbers of times that the ball is down, to n=1 the height is 8 inches, to n=2 the height is 4 inches.
An when n=5, the height is

the anwers is 0.5 inches
Answer:
<h2><em><u>62</u></em><em><u>.</u></em><em><u>2</u></em></h2>
Step-by-step explanation:
4n × 2 + 43
<em>[</em><em>By</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em>]</em>
= (4 ×2.4) × 2 + 43
= 9.6 × 2 + 43
= 19.2 + 43
= <em><u>62.2 (Ans)</u></em>