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Margaret [11]
3 years ago
8

The height of josie’s dog 11 1/4 inches to the nearest quarter inch and 11 inches to the nearest half inch.which measurement is

more precise
Mathematics
1 answer:
Lisa [10]3 years ago
3 0
Both measurements are correct if you're rounding the dogs height.

But the more precise measurement would be 11 1/4.

Mainly because its a smaller fraction so it has more meaning to it instead of just plain 11

It would get more precise as the fraction got larger
For example.

Not very precise 
11, 11 1/2, 11 1/4,   

Precise
11 1/8, 11 1/16 

Hope this helps!
Brainliest is always appreciated if you feel its deserved!<span />
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Can someone help me with this. Thx
insens350 [35]

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See this attachment

\boxed{\boxed{\sf{ x=5~and~y=-5 }} }

4 0
2 years ago
Read 2 more answers
A shirt costs $5 less than a sweater. Together they cost<br> $25. How much does the sweater cost?
Aleksandr-060686 [28]

Answer:

Shirt: $7.5

Sweater: $17.5

Step-by-step explanation:

25/2=12.5

Shirt is 5 less than Sweater

12.5-5=7.5

Add 5 to sweater cost

12.5+5=17.5

Shirt=7.5 Sweater=17.5

17.5+7.5=25

6 0
2 years ago
List four fractions that are equivalent to 3/5
kirill115 [55]

6/10, 9/15,12/20,15/25

Those are all equal to 3/5.

Hope this helps and hope you have a great day

8 0
3 years ago
Read 2 more answers
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
Can somebody pls help​
Delvig [45]
The answer is A domain
6 0
3 years ago
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