We separate equation by looking at x and y projection separately.
Let us look at the x projection first.
Motion starts with initial velocity

because there is no force acting along the x-axis we don't have any acceleration along the x-axis. Our equation would be:

Now our y equation will be a little bit more complicated. There is gravity working against our projectile and we also have to take into effect the hight from which the projectile is launched.
With all that in mind let us write the equation for y projection:

The term

represents gravity and as you can see it is negative, which means gravity is pulling our projectile down.
There is one more thing we can do. We can express initial velocity

in relation to circular motion used to launch the projectile.

Where r is the length of the letter used to launch the projectile, and

is angular velocity.
If we combine our x and y equations we can get the trajectory of our projectile.

This is the equation of a parabola. If you follow this link(https://www.desmos.com/calculator/vogcuygjhs) it will take to an interactive graph where you can see how trajectory looks like depending on some of the paramaters.
Answer:
Area = 22.3 m^2
Perimeter 27.4 m^2
Step-by-step explanation:
Perimeter = __ m
Area __ m^2
The area of the triangle is about 4.2,
The area of the square is 4,
The area of the semicircle is 14.1,
14.1 + 4.2 + 4 = 22.3
Area = 22.3 m^2
9.4 + 6 + 4 + 4 + 4 = 27.4
Perimeter = 27.4 m^2
Therefore the area of the shape is about 22.3 m^2 and the perimeter is about 27.4 m^2.
For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
Here are some formulas...
percent increase = (new number - original number) / original number...* 100
percent decrease = (original number - new number) / original number...* 100
============
a student raises her grade from a 75 to a 90....since it is going from a smaller number to a larger number, u have an increase
percent increase = (90 - 75) / 70....* 100
= 15/70 * 100
= 0.2142 * 100
= 21.42 rounds to 21.4% increase
-------------------------
36.50 on sale for 32.12...since it goes from a larger number to a smaller number, u have a decrease
percent decrease = (original number - new number) / original * 100
= (36.50 - 32.12) / 32.12...* 100
= 4.38 / 32.12...* 100
= 0.1363...* 100
= 13.63 rounds to 13.6% decrease
------------------------------
23.5 to 21.2......this is a decrease
percent decrease = (original number - new number) / original...* 100
= (23.5 - 21.2) / 23.5....* 100
= 2.3 / 23.5....* 100
= 0.0979 * 100
= 9.79 rounds to 9.8% decrease