−312−(−2)
=−72−(−2)
=−72−(−2)
=−32
=−112
1). [(6,1), (6,2), (6,3)] 2). [(0,5), (5,-1), (5,9)] 3). [(1,-6), (3,-5), (1,0)] 4). [(0,8), (1,7), (2,6)]. Which of the followi
Alex777 [14]
Again, look for repeated entries in the domain. If present, the relation cannot be a function. 1 maps 6 to 1, 2, and 3; 2 maps 5 to -1 and 9; 3 maps 1 to -6 and 0; and only 4 has no double mapping. Therefore 4 is a function and the answer.
since T is the midpoint of SU, then ST = TU.
![\bf \stackrel{10x-14}{\boxed{S}\rule[0.35em]{10em}{0.25pt}} T\stackrel{5x+16}{\rule[0.35em]{10em}{0.25pt}\boxed{U}} \\\\\\ \stackrel{ST}{10x-14}=\stackrel{TU}{5x+16}\implies 5x-14=16\implies 5x=30\implies x=\cfrac{30}{5}\implies x=6 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ST}{10(6)-14\implies 46}~\hfill \stackrel{TU}{TU=ST=46}~\hfill \stackrel{SU}{ST+TU=92}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B10x-14%7D%7B%5Cboxed%7BS%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20T%5Cstackrel%7B5x%2B16%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BU%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10x-14%7D%3D%5Cstackrel%7BTU%7D%7B5x%2B16%7D%5Cimplies%205x-14%3D16%5Cimplies%205x%3D30%5Cimplies%20x%3D%5Ccfrac%7B30%7D%7B5%7D%5Cimplies%20x%3D6%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10%286%29-14%5Cimplies%2046%7D~%5Chfill%20%5Cstackrel%7BTU%7D%7BTU%3DST%3D46%7D~%5Chfill%20%5Cstackrel%7BSU%7D%7BST%2BTU%3D92%7D)
If you would like to know the mean of the data set, you can calculate this using the following steps:
The <span>mean </span><span>of the data set is the sum of all the data values divided by the number of these values.
</span><span> </span>
<span>12, 17, 16, 10, 20, 13, 14, 14, 12, 12, 19, 18
</span>
<span>12 + 17 + 16 + 10 + 20 + 13 + 14 + 14 + 12 + 12 + 19 + 18 = 177
</span>the number of data values: 12
177 / 12 = 14.75
The correct result would be B. 14.75.
