All categories

3 years ago

How do you construct a 112.5 degree angle? (step by step) Please help =)

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

5 0

First you take a protractor and a pencil
next, you draw a horizontal line (red)
then find the value of the angle, and draw a line with the matched value (green)
please look at the image

You might be interested in

Help please I really need help and thank you :))))

77julia77 [94]

Answer:

14) x = 30°

15) x = 50°

Step-by-step explanation:

14) 60 + x = 90

x = 90 - 60

x = 30°

15) 130 + x = 180

x = 180 - 130

x = 50°

Hope this helps

3 0

1 year ago

Read 2 more answers

Affirmative action programs are primarily intended to . Allan Bakke believed he had been rejected for admission solely because o

Papessa [141]

Answer:

Encourage diversity

Race

Step-by-step explanation:

Took it on Edge :)

7 0

3 years ago

What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!

Radda [10]

Two main facts are needed here:

1. The logarithm $\log x$ , regardless of the base of the logarithm, exists for $x>0$ .

2. The square root $\sqrt x$ exists for $x\ge0$ .

(in both cases we're assuming real-valued functions only)

By (2) we know that $\sqrt{2x-1}$ exists if $2x-1\ge0$ , or $x\ge\dfrac12$ .

By (1), we know that $\log(\sqrt{2x-1}+3)$ exists if $\sqrt{2x-1}+3>0$ , or $\sqrt{2x-1}>-3$ . But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require $x\ge\dfrac12$ , so the function has domain $\left[\dfrac12,\infty)$ .

To determine the range, we need to know that, in their respective domains, $\sqrt x$ and $\log x$ increase monotonically without bound. We also know that $x=\dfrac12$ at minimum, at which point the square root term vanishes, so the least value the function takes on is $\log3$ . Then its range would be $[\log3,\infty)$ .