1. Find the area of parallelogram ABCD.
1 answer:
Answer:
1: C =69.3 m2
2: F = ll units
3. C: 3 in.
4. G =65 units
Step-by-step explanation:
1: C =69.3 m2
We see from the figure that height of the parallelogram ABCD is not known and the base is 10 m
Taking the right angled triangle the height is given by
Sine theta= height/hypotenuse
height = hypotenuse* sine theta
= 8* sine 60
= 8* 0.866= 6.928
Area of parallelogram= base * height
= 10 * 6.928
= 69.28
=69.3 m²
2: F = ll units
We see from the figure that height of the parallelogram DEFG is not known and the base is 13 cm
Area of parallelogram= base * height
143 = 13 * height
Height = 143/13= 11 units
3. C: 3 in.
The area of the triangle = 1/2 * base * height
Let the height be x then the base is 3x
54= 1/2*x*3x
54= 3x²/2
27= 3x²
x²=27/3
x²= 9
x= 3
The height is 3 inches
4. G =65 units
Area of the quadrilateral = 1/2 *PR*QO + 1/2 *PR*OS
= 1/2*13*4+ 1/2*13*6
=26+ 39
= 65 units
These measurements are given in the diagram .
You might be interested in
By definition, the average rate of change is given by:
We evaluate each of the functions in the given interval.
We have then:
For f (x) = x ^ 2 + 3x:
Evaluating for x = -2:
Evaluating for x = 3:
Then, the AVR is:
For f (x) = 3x - 8:
Evaluating for x =4:
Evaluating for x = 5:
Then, the AVR is:
For f (x) = x ^ 2 - 2x:
Evaluating for x = -3:
Evaluating for x = 4:
Then, the AVR is:
For f (x) = x ^ 2 - 5:
Evaluating for x = -1:
Evaluating for x = 1:
Then, the AVR is:
Answer:
from the greatest to the least value based on the average rate of change in the specified interval:
f(x) = x^2 + 3x interval: [-2, 3]
f(x) = 3x - 8 interval: [4, 5]
f(x) = x^2 - 5 interval: [-1, 1]
f(x) = x^2 - 2x interval: [-3, 4]