Question

1. Find the area of parallelogram ABCD.

Answer 1

Answer:

1: C =69.3 m2

2: F = ll units

3. C:  3 in.

4. G =65 units

Step-by-step explanation:

1: C =69.3 m2

We see from the figure that height of the parallelogram ABCD is not known and the base is 10 m

Taking the right angled triangle the height is given by

Sine theta= height/hypotenuse

height = hypotenuse* sine theta

         = 8* sine 60

         = 8* 0.866= 6.928

Area of parallelogram= base * height

                   = 10 * 6.928

                   = 69.28

                  =69.3 m²

2: F = ll units

We see from the figure that height of the parallelogram DEFG is not known and the base is 13 cm

Area of parallelogram= base * height

                  143 = 13 * height

           Height = 143/13= 11 units

3. C:  3 in.

The area of the triangle = 1/2 * base * height

Let the height be x then the base is 3x

54= 1/2*x*3x

54= 3x²/2

27= 3x²

x²=27/3

x²= 9

x= 3

The height is 3 inches

4. G =65 units

Area of the quadrilateral = 1/2 *PR*QO + 1/2 *PR*OS

                                      = 1/2*13*4+ 1/2*13*6

                                        =26+ 39

                                        = 65 units

These measurements are given in the diagram .