First calculate the distance covered going down:
d_down = (16 m / s) * 8 s = 128 m
Then the distance going up is:
d_up = 71 m
So the distance from the ledge to the nest is:
d = 128 m – 71 m = 57 m
Therefore the elevation is:
<span>elevation = 1364 m + 57 m = 1421 m</span>
Answer:
there is no collision between the particles
Step-by-step explanation:
for the first particle
x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π
for the second particle
x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π
then for the collision
x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t
y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2
since 1/3 ≠ 2 there is no collision between the particles
3x1000+2x100+4x10+6x1+7x(1/10)+8x(1/100)
9514 1404 393
Answer:
∠CAB = 28°
∠DAC = 64°
Step-by-step explanation:
What you do in each case is make use of the relationships you know about angles in a triangle and around parallel lines. You can also use the relationships you know about diagonals in a rectangle, and the triangles they create.
<u>Left</u>
Take advantage of the fact that ∆AEB is isosceles, so the angles at A and B in that triangle are the same. If we call that angle measure x, then we have the sum of angles in that triangle is ...
x + x + ∠AEB = 180°
2x = 180° -124° = 56°
x = 28°
The measure of angle CAB is 28°.
__
<u>Right</u>
Sides AD and BC are parallel, so diagonal AC can be considered a transversal. The two angles we're concerned with are alternate interior angles, so are congruent.
∠BCA = ∠DAC = 64°
The measure of angle DAC is 64°.
(Another way to look at this is that triangles BCE and DAE are congruent isosceles triangles, so corresponding angles are congruent.)
You can use the factors of the volumes 24, 27 and 48:
For example:
8 by 3 by 1 is a total volume of 24
or if you know that 4 times 2 is 8:
4 by 2 by 2
and so on
