Answer: Rs. 5,033.30
Step-by-step explanation:
Total employees = 15 + 32 + 65 + 79 + 90 + 57 + 36 + 14 = 388
Median position = 388/2 = 194
Median therefore lies in range where cumulative employees is 194:
= 15 + 32 + 65 + 79 = 191
Median therefore lies in range after 4,000 - 4,999 which is 5,000 - 5,999.
Median = Lower limit of median range + range of median range * (median position - cumulative frequency up to median range) / frequency of median range
= 5,000 + 999 * (388/2 - 191)/90
= 5,000 + 33.3
= Rs. 5,033.30
Answer:
x=-2
y=4
Using the equations I have been given, I will substitute "x+6" in place of y
3x+2(x+6)=2
distribute:
3x+2x+12=2
combine like terms:
5x+12=2
sub. 12 from both sides:
5x=-10
x=-2
Since we have our "x" value we can plug it in to find our "y" value
3(-2)+2Y=2
-6+2y=2
2y=8
y=4
Hope this helps!
Im not 100% sure but I think it’s X-8.8
2 W + 5 L = 750 ft
5 L = 750 - 2 W
L = 150 - 2 W / 5
A ( W ) = W * ( 150 - 2 W / 5 )
A function that models the total area:
A ( W ) = 150 W - 2 W² / 5
A` ( W ) = 150 - 4 W / 5
150 - 4 W / 5 = 0
4 W / 5 = 150
W = 187.5 ft
The largest possible area:
A = 150 * 187.5 - (2 * 187.5² ) / 5 = 28,125 - 14,062.5 = 14,062.5 ft²