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dmitriy555 [2]
3 years ago
6

Find the solution set for this inequality:

Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0
Answer is c I believe, so sorry if I’m wrong
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5x - 8x + 9 = 2x + 39​
docker41 [41]

Answer:

pliz send me the formula, only dsn I can solve your answer

4 0
3 years ago
Read 2 more answers
Help please with this
kupik [55]

Answer:

85 and 91

Step-by-step explanation:

7 0
2 years ago
James measured a piece of construction paper to be 6 3/4 inches wide and 9 2/3 inches long. What is the area of the piece of con
ivolga24 [154]

Answer:

The area of the piece of construction paper is \frac{261}{4} inches^2

Step-by-step explanation:

Length of construction paper =6 \frac{3}{4} inches

                                                 =\frac{27}{4} inches

Width of construction paper = 9 \frac{2}{3} inches

                                              = \frac{29}{3} inches

Area of construction paper =Length \times Width

Area of construction paper = \frac{27}{4}  \times \frac{29}{3}

                                             = \frac{261}{4} inches^2

Hence the area of the piece of construction paper is \frac{261}{4} inches^2

7 0
3 years ago
Pls guys help me pls ​
galina1969 [7]

Answer:

x < 5

I think the answer is A

8 0
3 years ago
The following are the temperatures of 10 days in winter in °C. − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 Work out the mean
marissa [1.9K]

The mean temperature of the given data − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 is 1.9

mean= 1.9

<h3>What is mean of the data?</h3>

The mean, or average, is calculated by adding up the data and dividing by total number of data.

Given data: − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3

Now, mean =   \frac{sum \;of\; observation}{Total \;number \;of \;observation}

mean = \frac{(-3)+ 0+10+2+8+(-5)+ (-1)+ 9+2+(-3)}{10}

           = \frac{19}{10}

mean= 1.9

Hence, the mean of − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3  is 1.9

Learn more about mean here:

brainly.com/question/22871228

#SPJ1

3 0
2 years ago
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