ABCD is a plane quadrilateral and E is any point on AD. EF is drawn parallel
1 answer:
<u>Try this</u>:
FA/AB = AE/AD by the side-splitter theorem because EF ║ BD
∠FAE ≅ ∠BAD because an angle is congruent to itself
AE/AD = EG/DC by the side-splitter theorem because EG ║ CD
∠AEG ≅ ∠ADC because they are corresponding angles where a transversal crosses parallel lines
quadrilateral AFGE is similar to quadrilateral ABCD by SASAS similarity of quadrilaterals
From here, there are numerous ways to reach the conclusion. One of them is ...
∠AFG ≅ ∠ABC by corresponding angles of similar quadrilaterals
∴ FG ║ BC because ∠AFG and ∠ABC are corresponding angles where transversal AB crosses FG and BC
You might be interested in
We'll do the first one. I can't read the variable, but it looks like a 
so that's what I'll use, but it doesn't matter.
First, get the variable by itself:
You get that before you multiply each side by two.
Now, you color the line so that all values that are less than 6 are shaded, so you put an open circle at 6 since it's not included and then you shade everything to the left.
First, get the variable by itself:
You get that before you multiply each side by two.
Now, you color the line so that all values that are less than 6 are shaded, so you put an open circle at 6 since it's not included and then you shade everything to the left.