Here speed of first train is slower than speed of second train. So if they catch up , the distance traveled will be same since they left the same station at different times.
But the time traveled will be different .
Let us say the two trains meet at time t ,
Distance = speed * time
Distance traveled by first train = 40 t
Since second train is leaving after three hours , so
Distance traveled by second train = 60(t-3)
As discussed earlier, distance traveled will be same, so

distributing 60 over t-3




t=9
So the second train will meet the first at 9 p.m.
(3 + (2/3))(2+(1/2) = 3*2+2*(2/3)+3*(1/2)+((2/3)(1/2)) = 6+(4/3) +(3/2) + (2/6) = 6 + ((8+9+2)/6) = 6 + (19/6) = 6 + 3 + 1/6 = 9 + 1/6 miles = D
Answer:
Step-by-step explanation:
20/12 = 1 2/3
30 ÷ 1 2/3
= $18
9514 1404 393
Answer:
A. z increased by 8
Step-by-step explanation:
When a positive value is added, the original value (z) is <em>increased</em>.
z + 8 ⇔ z increased by 8
Answer:
whats the question?
Step-by-step explanation: