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Kobotan [32]
4 years ago
12

How can we calculate the value of angle

Mathematics
1 answer:
Papessa [141]4 years ago
7 0
Where is the angle? you dont have it posted
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What’s the answer the multiple choice is there to please don’t guess
Anit [1.1K]
<h3>Answer: Point E is located at (2, 3)</h3>

====================================

Explanation:

The sequence PQRST has T as the last letter.

The sequence ABCDE has E as the last letter

The two letters T and E pair up or they correspond. So T will rotate to land on point E. Or T will rotate to point E's location.

Point T is at location (-3,2). So x = -3 and y = 2.

-------

Use the rule

(x,y) ---> (y, -x)

which is the rule we use when we rotate any point 90 degrees clockwise around the origin. We swap the x and y coordinates, then change the sign of the second coordinate (after the swap happens).

This means,

(-3, 2) ----> (2, -(-3)) = (2, 3)

or simply

(-3, 2) ---> (2, 3)

6 0
3 years ago
Pls help me guys :( you guys are talented
4vir4ik [10]
D\

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5 0
3 years ago
Given the initial inequality −4 (7)<br> c. (−4) = (7)
Katen [24]

Answer:

Step-by-step explanation:

Simplify 4*(7-c)

4

⋅

(

7

−

c

)

4

⋅

(

7

-

c

)

Apply the distributive property.

4

⋅

7

+

4

(

−

c

)

4

⋅

7

+

4

(

-

c

)

Multiply.

Tap for more steps...

Multiply 4

4

by

7

7

.

28

+

4

(

−

c

)

28

+

4

(

-

c

)

Multiply

−

1

-

1

by

4

4

.

28

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28

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28

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6 0
3 years ago
Read 2 more answers
the lengths of the sides of a triangle are consecutive even integers. the perimeter is 42. what is the length of the longest sid
Alex

Answer:

Assuming x as the length of the longest side, x is 16 units.

Step-by-step explanation:

x+(x-2)+(x-4)=42\\3x-6=42\\3(x-2)=42\\x-2=14\\x=16

5 0
3 years ago
Simplify: (cos^2x-1)/cosx+1
gizmo_the_mogwai [7]

The solution would be like this for this specific problem:

(cos^2x-1)/cosx+1

cos^2x-1= (cosx+1)(cosx-1)

cosx-1

<span>I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

5 0
3 years ago
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