Step-by-step explanation: Given that Sheila loves to eat chicken tenders. A small order comes with 5 chicken tenders, and a large order comes with 8 chicken tenders.

Last month, Sheila ordered chicken tenders a total of 7 times. She received a total of 50 chicken tenders.

We are to find the number of large chicken tenders received by Sheila.

Let x and y represents the number of small orders and large orders respectively of chicken tenders.

Then, according to the given information, we have

$x+y=7\\\\\Rightarrow x=7-y~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$5x+8y=50\\\\\Rightarrow 5(7-y)+8y=50~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\Rightarrow 35-5y+8y=50\\\\\Rightarrow 3y=50-35\\\\\Rightarrow 3y=15\\\\\Rightarrow y=\dfrac{15}{3}\\\\\Rightarrow y=5.$

Thus, the required number of large order of chicken tenders is 5.

5 0

3 years ago

Lucinda lives .6 miles from the park. Angie lives 10 times as far from the city park as Lucinda. Stacy lives 1/10 of a mile furt

weqwewe [10]

Answer: 6.4 miles

Step-by-step explanation:

Lucinda lives 0.6 miles from the Park and Angie lives 10 times as far as this.

= 0.6 * 10

= 6 miles

Stacy lives 1/10 miles further than Angie;

= 6 + 1/10

= 6.1 miles

She lives 3/10 of a mile closer than Gabriel which means that Gabriel lives 3/10 of a mile further from the park than Lucinda;

= 6.1 + 3/10

= 6.4 miles

4 0

3 years ago