Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria
Answer:

Step-by-step explanation:

<u>1.Find the LCM(Least Common Multiple).</u>
That would be 20.
<u>2.Multiply so all denominators are equal.</u>

<u>3. Add</u>
<u></u>
<u>4. Simplify</u>
<u></u>
The answer is 33 because 40*0.825 or 40*82.5% is 33 men.