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Murljashka [212]
3 years ago
13

Write an equation of a line that goes.through point (0,1) and has.a.slope of 0

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

y=1

Step-by-step explanation:

If the slope of a line is 0, then the line is horizontal.

From there, all you have to do is find y.

This is easy because all you have to do is write down the y-coordinate that's listed.

So, the equation would be y=0x+1 which is y=1.

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Sampson solves the inequality as shown below.
astraxan [27]

Answer:

subtract 3 from both sides

Step-by-step explanation:

7 0
3 years ago
What is the value of v
const2013 [10]

Answer:

v=9

Step-by-step explanation:

12v-44+6v+23+15v-9+v+30+6v=360

40v=360

v=9

6 0
2 years ago
Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on
Goryan [66]

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

4 0
3 years ago
The
m_a_m_a [10]

Answer:

F) standard form

Step-by-step explanation:

4 0
3 years ago
the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle
nikdorinn [45]
l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}
length\approx9.71cm;\ width\approx17.71cm
4 0
3 years ago
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