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dedylja [7]
3 years ago
5

BeeGood Honey recently expanded its distribution to include 74,600 households within the Southwestern United States in an area w

ith a population of 300,000 people. Of these newly targeted households, 35,700 have previously purchased the category. Last quarter the region's total dollar sales for the honey category reported at $827,000, driven by the three largest brands: StingerSue, Sweetness, and BeeGood with sales of $304,000, $200,000 and $94,600 respectively. In the same quarter, unit purchases of BeeGood Honey brand amounted to 38,500 jars across the region. Among the 25,500 households that bought BeeGood, total purchases of honey were reported at 60,100 jars. What is BeeGood's Brand Penetration (%)
Business
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer: 34.2%

Explanation:

Brand penetration is meant to measure the number of people who bout a certain brand as a percentage of the population that the company target to sell to.

The formula is;

= No. of Households who bought BeeGood Honey/ No. of targeted Households

= 25,500/74,600

= 34.2%

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Starting the next task before the first task is complete is lead.

In the eyes of some businesses, a "lead" is a contact that has already been identified as a potential client, whereas for other businesses, a "lead" is any sales contact. However, a lead's potential to become a future client is the same regardless of how it is defined.

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2 years ago
The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana
storchak [24]

Answer:

a) P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

b) P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

c) P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

X \sim N(502,100)  

Where \mu=502 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(502-10 < \bar X < 502+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

X \sim N(515,100)  

Where \mu=515 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(515-10 < \bar X < 515+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

X \sim N(494,100)  

Where \mu=494 and \sigma=100

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)

And for this case we want this probability:

P(494-10 < \bar X < 494+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

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Answer:

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All the above are important for building a financial future as without this information we cannot complete our financial activities, Like if we do not have the tax information, we will not be able to fill our taxes properly no matter we are self-employed or doing a job. Also for self-employment and our own business, we need investment, and for that, we need to find out the investors, Also we need to find out the loans that are available to us as then only we will be able to arrange money when required. And we need to know what is right for us, self-employment or a job.

Explanation:

Please check the answer.

7 0
3 years ago
The following transactions were completed by The Irvine Company during the current fiscal year ended December 31: Feb. 8 Receive
nirvana33 [79]

Answer:

See every requirement in details bellow

Explanation:

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3 years ago
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xxMikexx [17]

Answer:

C. ​the front page test

Explanation:

The front page test -

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Same is the case with Haley , since she is aware that she can make a lot of money from the large hospital network , but she is more concern about the threat of being caught and from the reaction of the out side public .

Hence , the correct answer is  the front page test  .

7 0
3 years ago
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