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2 years ago

X+4 > -15. What does x equal

Mathematics

1 answer:

miss Akunina [59]2 years ago

8 0

X+4>-15
x>-15-4
So x>-19
so the value of xis greater than -19

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Find the equation of the line<br><br> Y= __x + __

djyliett [7]

Answer:

y=2x+5

Step-by-step explanation:

0,5

0,7

7-5 is 2

2/0 is 2

to check answer:

(2*0)+5

0+5

8 0

2 years ago

Read 2 more answers

3x2 - 5x + 6) + (9 - 8x - 4x2)

Ksju [112]

Answer:

13-13x

Step-by-step explanation:

3*2=6

(6-5x+6) + (9-8x-8)

Combine Like Terms

(12-5x) + (1-8x)

Put x on one side and numbers on the other.

(12+1) + (-5x+ (-8x))

13-13x

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2 years ago

What is the value of x-y if x= -1/5 and y=7/15

Vitek1552 [10]

The answer to this problem is -0.66666

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3 years ago

PLEASE HURRY AND HELP ...

Nonamiya [84]

Answer:

Volume= 35.257

Step-by-step explanation:

∙ x V cylinder = π r 2 h

here diameter = 3.25 ⇒ radius = 1.625 ⇒ volume = π × ( 1.625 ) 2 × 4.25× × × × ≈ 35.257 cubic inches

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3 years ago

Write and equation for the shift of the parent graph y=1/x

SashulF [63]

You can think of this equation as $\bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}$

and thus apply the transformations to it as such

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

1) D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7

7 0

2 years ago