Area=pi r squared
area=3.14 x 10squared
area= 314
the answer is 314
The line equation in slope-intercept form is y=mx+b
You have one line with a y-intercept at 1 and a slope of -3 -> y=-3x+1
and another with a y-intercept at -1 and a slope of 
-> 
The area marked is below the first line and above the second one -> replace = with < and >:
y<-3x+1
Which is the system of linear inequalities shown in the graph
5x3-x+ 9x7 +4 +3x11
Answer:
115-X
Explanation:
First you multiply the 5x3
<u>15</u>-X+9x7+4+3x11
then the 9x7
15-X+<u>63</u>+4+3x11
then the 3x11
15-x+63+4+<u>33</u>
Now once you have completed the multiplication step you move on to <u>calculating the sum.</u> (Adding all the positive numbers)
<u>15</u>-x<u>+64+4+33</u>
115-x
4ry + 3rz + 8xy + 6xz
r(4y) + r(3z) + 2x(4y) + 2y(3z)
r(4y + 3z) + 2x(4y + 3z)
(r + 2x)(4y + 3z)
The answer is D.
Answer:
C. To make sure all temporary accounts have a zero balance.
Step-by-step explanation:
The closing process is an accounting method applied at the end of the year with the purpose of ensuring that all accounts are ready for the preparation of financial statements, as well as the start of a new accounting year.
Temporary accounts are made permanent. Also, the accounts for the present year are zeroed. By so doing, only the current balance will be reflected in the new year accounts.
