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Luba_88 [7]
2 years ago
8

3x−1−(x+3)=1 PLEASE HELP IDK HOW TO DO IT

Mathematics
2 answers:
torisob [31]2 years ago
7 0

Answer:

x = 5/2

x = 2 1/2

x = 2.5

Step-by-step explanation:

3x - 1 - (x + 3) = 1

3x - 1 - x - 3 = 1

2x - 1 - 3 = 1

2x - 4 = 1

2x = 1 + 4

2x + 5

2x = 5

x = 5/2 → 2 1/2 → 2.5 ( can be written in any of these forms depending on what you need to do)

<em>Hope this helped! :)</em>

Allisa [31]2 years ago
5 0

Answer:

<h2>x = 5/2</h2>

Step-by-step explanation:

3x−1−(x+3)=1

<u>First remove the bracket</u>

That's

3x - 1 - x - 3 = 1

<u>Group the constants at the right side of the equation</u>

That's

3x - x = 1 + 1 + 3

Simplify

We have

2x = 5

Divide both sides by 2

That's

2x / 2 = 5/2

<h3>x = 5/2</h3>

Hope this helps you

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Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 2x-y=
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Answer:

The system of linear equations has infinitely many solutions

Step-by-step explanation:

Let's modified the equations and find the answer.

Using the first equation:

2x-y=5 we can multiply by 2 in both sides, obtaining:

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4x-2y=10 which is equal to:

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Taking into account that from the first equation we know that: 4x=2y+10, we can express the second equation as:

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(2+k)y=2-10

(2+k)y=-8

y=-8/(2+k)

Because (-8) is being divided by (2+k), then (2+k) can't be equal to 0, so:

2+k=0 if k=-2

This means that k can be any number different than -2, and for each of these solutions, there is a different solution for y, allowing also, different solutions for x.

For example, if k=0 then

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4x=2y+10 if y=-4 then x=(-8+10)/4=0.5

Now let's try with k=-1, then:

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8 0
3 years ago
Investment of 1000 at 16% interest rate for 20 years
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This might be wrong but, 320.

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3 years ago
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nataly862011 [7]
<span>The slope of a line is -3
</span><span>perpendicular  lines, slope is opposite and reciprocal
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Finger [1]

Answer:

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Step-by-step explanation:

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When comparing more than two treatment means we use ANOVA because a t test increases the risk of type 1 error  .

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