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3 years ago

Solve the equation!!! 7x + 10 = ? When x = 10 Show work!!!!

2 answers:

5 0

Hi there!

Since x is 10, we can just plug it into the equation.

= 7*10 + 10
= 70 + 10
= 80

So, the answer is 80.

Hope this helps!

zaharov [31]3 years ago

3 0

7x + 10

x = 10

Substitute:

7 times 10 = 70

70 + 10 = 80

The answer is 80.

Hope this helped

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2 years ago

A recipe calls for 4 carrots for every 2 cups of water. Which expression can be used to find the number of carrots needed

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Answer:

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Step-by-step explanation:

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3 years ago

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If f(x)=-x^2+6x-1 and g(x) =3x^2-4x-1, find (f-g)(x)

asambeis [7]

Answer:

Step-by-step explanation:

Given,

$f(x)=-x^{2} +6x-1\\g(x)=3x^{2} -4x-1$

we know,

(f-g)(x)=f(x)-g(x)

So, here we get

(f-g)(x)

=f(x)-g(x)

= $-x^{2} +6x-1-(3x^{2} -4x-1)$

= $-x^{2} +6x-1-3x^{2} +4x+1$

= $-x^{2}-3x^{2} +6x+4x-1+1$

= $-4x^{2} +10x$

So, the answer is

$-4x^{2} +10x$

8 0

3 years ago

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21. In 4 + In(4x - 15) = In(5x + 19)

Alexxx [7]

Answer:

$x=-30;\quad \:I\ne \:0$

Step-by-step explanation:

$In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)$

$\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\$

$\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\$

$\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:$

$\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0$

3 0

3 years ago

What is the domain of the function graphed below?

JulijaS [17]

Answer:

Domain: 0, 5

Range: 0, 2

Step-by-step explanation:

The Domain is the first coordinate which is x.

The Range is the second coordinate which is y.

Hope This Helps :)

5 0

2 years ago