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3 years ago

Solve the equation!!! 7x + 10 = ? When x = 10 Show work!!!!

2 answers:

5 0

Hi there!

Since x is 10, we can just plug it into the equation.

= 7*10 + 10
= 70 + 10
= 80

So, the answer is 80.

Hope this helps!

zaharov [31]3 years ago

3 0

7x + 10

x = 10

Substitute:

7 times 10 = 70

70 + 10 = 80

The answer is 80.

Hope this helped

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7x + 2y = 7<br> -14x + 2y = -11<br> Solve by substitution

kvasek [131]

Answer:

x = 6/7, y = 1/2

Step-by-step explanation:

7x + 2y = 7

-14x + 2y = -11

1) 7x + 2y = 7

2y = 7 - 7x

2) -14x + 2y = -11

-14x + 7 - 7x = -11

- 21x = -11-7

- 21x = - 18

x = 18/21 = 6/7

3) 2y = 7 - 7x = 7 - 7*(6/7) = 7 - 6 = 1

2y = 1

y = 1/2

7 0

3 years ago

12,13,15,16,19,19,19,20,21,25 find the mean

lesya [120]

Answer:

17.9

Step-by-step explanation:

Add all of the numbers together.

You get 179

Divide by the amount of numbers, 10

you get 17.9

Happy Valentines day! (3

Please give me brainliest!

5 0

3 years ago

Read 2 more answers

Hello !!! please help me <3 will give brainle and 25 points please help !!!!

Hitman42 [59]

answer: 375

Step-by-step explanation:

panda bear caps: 25

they ordered 100 in total

25/100 = 1/4, a quarter

then you find a quarter of 1500

1500/4= 375

4 0

2 years ago

√3×sinx+cosx=0 tmf nghiệm

Crazy boy [7]

Answer:

x= -30

Step-by-step explanation:

√3×sinx+cosx=0

√3sinx=-cosx

√3sinx/-cosx=1

-sinx/cosx=1/√3

-tanx=1/√3

(tan(180-30))=1/√3

tan(-30)=1/√3

Therefore, x= -30

7 0

2 years ago

According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i

Ierofanga [76]

Answer:

a) $P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

b) $P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

c) For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

And replacing we got:

$P(X\geq 8)=0.0000779$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n=10 ,p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:

$X \sim Binom(n=10, p=0.2)$

Part a

We want to find this probability:

$P(X=2)$

And using the probability mass function we got:

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

Part b

For this case we want this probability:

$P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

We can find the individual probabilities and we got:

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

Part c

For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

3 0

3 years ago