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nevsk [136]
3 years ago
7

Marlo buys 6 feet of ribbon to make bracelets she needs 18 inches of ribbon to make one bracelet how many bracelets Ken Marlow m

ake if she uses all the ribbons she buys
Mathematics
2 answers:
Mariulka [41]3 years ago
7 0
She can make 4 bracelets
sergey [27]3 years ago
3 0

Answer:

4

Step-by-step explanation:

1 ft = 12 inches. 12 times 6 is 72. 72 divided by 18 is 4. She can make four long ribbons.

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Will make brainiest and you only have to answer at least one question.
MariettaO [177]

Answer:

see below

Step-by-step explanation:

342 m/s    *  1.09361329834  yd /m  *  1 mile / 1760 yards = .21251 mi/s

1500 mi / hr  *   1609.344 meters / mile   * 1 km / 1000 m = 2414 km/hr

8 0
2 years ago
A rectangle with a width of 3 units and a length of x +5
Luden [163]

Answer:

The area is 45 units squared

Step-by-step explanation:

If the rectangle's width is 3 units, and the length is 5 times then:

5 x 3 = 15

So the length is 15 units

The area is length times width

15 x 3 = 45

The area is 45 units squared

7 0
3 years ago
What is the equation of a line passing through (-3, 7) and having a slope of -1/5 ? A. y = -5x + 22 B. y = 5x + 22 C. y=1/5x+32/
bogdanovich [222]

Answer:

  D.  y = -1/5x +32/5

Step-by-step explanation:

The equation of the line passing through point (h, k) with slope m can be written ...

  y = m(x -h) +k

Filling in your given values, the equation is ...

  y = -1/5(x -(-3)) +7

  y = -1/5x -3/5 +7 . . . . eliminate parentheses

  y = -1/5x +32/5 . . . . . combine constants

5 0
4 years ago
If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e
Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

  • <em>99 is an outlier of pet group</em>
  • <em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

n = 15

The quartiles positions are:

Q_1 = \frac{n + 1}{4}

Q_1 = \frac{15 + 1}{4}

Q_1 = \frac{16}{4}

Q_1 = 4th

Q_3 = Q_1 \times 3

Q_3 = 4th \times 3

Q_3 = 12th

So, we have:

Q_1 = 4th

Q_3 = 12th

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

Q_1 = 68

Q_3= 79

The lower and upper limits of the outlier are:

L = Q_1 - 1.5 \times (Q_3 - Q_1)

U = Q_3 + 1.5 \times (Q_3 - Q_1)

So, we have:

L = 68 - 1.5 \times (79 - 68)

L = 51.5

U = 79+ 1.5 \times (79 - 68)

U = 95.5

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

5 0
3 years ago
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =
BabaBlast [244]

Answer:

4c² + 11cd + 5d

Step-by-step explanation:

(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)

-4c² + 7cd + 8d - 3d + 8c² + 4cd (opening bracket)

8c²-4c²+7cd + 4cd + 8d - 3d

= 4c² + 11cd + 5d

4 0
3 years ago
Read 2 more answers
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