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Yuliya22 [10]
3 years ago
11

Find the gcf and use it to reduce 36/63​

Mathematics
2 answers:
alisha [4.7K]3 years ago
4 0

Answer:

\frac{4}{7}

Step-by-step explanation:

The greatest common factor of 36 and 63 is 9.

Thus, \frac{36}{63} = \frac{4}{7} since (36 ÷ 9 = 4) and (63 ÷ 9 = 7).

aksik [14]3 years ago
3 0

Answer:

4/ 7

Step-by-step explanation:

you list the factors of each number  so  factors of 36 are 1 2 3 4 6 9 12 18 36 and factors of 63 are 1 , 3 , 7 , 9 , 21 and 63  as the highest common factor in each number is 9 you do 36 ÷ 9 = 4 which will be the numerator and 63÷ 9 = 7 which will be the denominator so the simplest form of 36/63 is 4/7

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Step-by-step explanation:

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Normal probability distribution

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The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 26, \sigma = 6, n = 62, s = \frac{6}{\sqrt{62}} = 0.762

(a)

What is the likelihood the sample mean is at least $27.00?

This is 1 subtracted by the pvalue of Z when X = 27. So

Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{s}

Z = \frac{27 - 26}{0.762}

Z = 1.31

Z = 1.31 has a pvalue of 0.9049

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(b)

What is the likelihood the sample mean is greater than $25.00 but less than $27.00?

This is the pvalue of Z when X = 27 subtracted by the pvalue of Z when X = 25. So

X = 27

Z = \frac{X - \mu}{s}

Z = \frac{27 - 26}{0.762}

Z = 1.31

Z = 1.31 has a pvalue of 0.9049

X = 25

Z = \frac{X - \mu}{s}

Z = \frac{25 - 26}{0.762}

Z = -1.31

Z = -1.31 has a pvalue of 0.0951

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c)Within what limits will 90 percent of the sample means occur?

50 - 90/2 = 5

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Between the 5th and the 95th percentile.

5th percentile

X when Z has a pvalue of 0.05. So X when Z = -1.645

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X = 24.75

95th percentile

X when Z has a pvalue of 0.95. So X when Z = 1.645

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1.645 = \frac{X - 26}{0.762}

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X = 27.25

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