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AysviL [449]
3 years ago
5

What are 4 consecutive odd integers where the product of the two smaller integers is 64 less than the product of the two larger

integers?
Mathematics
1 answer:
Nana76 [90]3 years ago
5 0
2n+1=2n+3=2n+5=2n+7-64
4nexponet2+8n+34exponetof2+25+34-64
8n+3=24n-29
16n=32
n=2
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What is the answer to 3s-4=1-3s<br> &amp;<br> Ax+by=c <br><br> Thanks
otez555 [7]
1. S= 5/6 or 0.833333

2. 0
6 0
3 years ago
Lowest common multiple of 28 and 42
Delicious77 [7]
7 is the lowest common multiple i think
8 0
4 years ago
Read 2 more answers
23 x 32 is the prime factorization for which one of these choices?
antoniya [11.8K]
<h2><u>Answer:</u></h2>

⟶ 2³ × 3² is the prime factorization for which one of these choices?

Let's check,

1) 6 = 3 × 2 [So, obviously not this choice]

2) 25 = 5 × 5 = 5² [Not this either]

3) 36 = 3 × 2 × 2 × 3 = 3² × 2² [Doesn't match with 2³ × 3²]

4) 72 = 2 × 2 × 2 × 3 × 3 = <u>2</u><u>³</u><u> </u><u>×</u><u> </u><u>3</u><u>²</u><u> </u>[Matches]

⟶ The answer is, choice <u>7</u><u>2</u><u>.</u>

\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}

3 0
3 years ago
Check answer please
Cerrena [4.2K]
The fourth or the D) Option is correct.

To find the new induced matrix via a scalar quantified multiplication we have to multiply the scalar quantity with each element surrounded and provided in a composed (In this case) 3×3 or three times three matrix comprising 3 columns and 3 rows for each element which is having a valued numerical in each and every position.

Multiply the scalar quantity with each element with respect to its row and column positioning that is,

Row × Column. So;

(1 × 1) × 7, (2 × 1) × 7, (3 × 1) × 7, (1 × 2) × 7, (2 × 2) × 7, (3 × 2) × 7, (1 × 3) × 7, (2 × 3) × 7 and (3 × 3) × 7. This will provide the final answer, that is, the D) Option.

To interpret and make it more interesting in LaTeX form. Here is the solution with LaTeX induced matrix.

\mathcal{A = \begin{bmatrix}1 & 0 & 3 \\ 2 & -1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad 7A = 7 \times \begin{bmatrix}1 & 0 & 3 \\ 2 & - 1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad \begin{bmatrix}7 \times 1 & 7 \times 0 & 7 \times 3 \\ 7 \times 2 & 7 \times -1 & 7 \times 2 \\ 7 \times 0 & 7 \times 2 & 7 \times 1 \\ \end{bmatrix}}

\therefore \quad \begin{\bmatrix}7 & 14 & 0 \\ 0 & -7 & 14 \\ 21 & 14 & 7 \end{bmatrix}

Hope it helps.
5 0
3 years ago
Find the area under the standard normal distribution curve for the following intervals. a. Between z = 0 and z = 2.0 b. To the r
vesna_86 [32]

Answer:

a) P(0

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

P(0

b) P(Z>1.5) =1-P(Z

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

P(Z>1.5) =1-P(Z

c) P(z

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

P(z

d) P(-2.78

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

P(-2.78

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Part a

We want this probability:

P(0

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

P(0

Part b

For this case we want this probability:

P(Z>1.5)

And we can use the complement rule and we have:

P(Z>1.5) =1-P(Z

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

P(Z>1.5) =1-P(Z

Part c

We want this probability:

P(z

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

P(z

Part d

We want this probability:

P(-2.78

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

P(-2.78

5 0
4 years ago
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