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3 years ago

Which of these triangle pairs can be mapped to each other using a reflection

Mathematics

1 answer:

tia_tia [17]3 years ago

8 0

Help me! I’ll mark you brainly!

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09:30 to 17:00 minus 30 minutes How many hours is that ?

pentagon [3]

Answer:

7 hours

Step-by-step explanation:

9 : 30 to 17:00 = 7 hours 30 minutes

Minus 30 minutes = 7 hours

6 0

3 years ago

Please helppp!!!!!!!!!!!!!

yKpoI14uk [10]

Step-by-step explanation:

answer is d and b.

they both lie in same line

6 0

3 years ago

Evaluate [20x ÷ 5 · (-x)] + 3

Anna35 [415]

Order of operations, the order in which to do them
pemdas
parenthasees
exponents
multiplication or division (whichever comes first)
addition or subtraction (whichever comes first)
so

inside parenthaees first
20x/5=4x

now we has
[4x*(-x)]+3
multiply
4x*-x=-4x²

now we has
[-4x²]+3
-4x²+3 is the eavlauted form

8 0

3 years ago

Volume of a sphere that has a diameter of 8 inches PLEASE HELP

tatiyna

Answer: 268.08in³

Formula:

V=4 π r³

d= 2r

Solving for V:

V=1 π d³=1·π·83≈268.08257in³

6 6

4 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

Answer:

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

Solution:

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago