Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
Answer:
12(2x-1)
Step-by-step explanation:
Answer:
<h2>d. 1 is the right answer.</h2>
Probability is the extent to which an event is likely to occur. It is the likelihood of sth to happen.
In maths it is measured by the ratio of the favourable cases to the whole number of cases possible.
For instance
there are 5 black balls and 2 white balls of same shape and size.
If you picked one out of a bag it is more likely for you to pick a black one rather than a white one as it has more in number.
So black balls have more probability.
And to find out probability of this above given event,
Sample space n(S) = 5+2 = 7
No. Of black balls n(B) = 5
No. Of white balls n(W) = 2
Probability of black ball p(B) = n(B)/n(S)
=5/7
And in the same way, p(W) = 2/7
Answer:
what is the expression? please provide an expression.
