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Tom [10]
3 years ago
14

perry divides up some candy to give equally9 to his six friends. If C represents the total amount write an expression to represe

nt how much candy each crime receives
Mathematics
1 answer:
inessss [21]3 years ago
8 0

Answer:

c/6

Step-by-step explanation:

If c amount of candy is divided amongst the six friends, each friend will get c/6 amount of candy. Hope this helps!

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Someone please help me on this question:
Katena32 [7]

Answer: C

Step-by-step explanation: because her earnings which means net income is 120 because 15 hours times 8 hours is 120 so she cant make more than that if she gets paid $ 8 for 15 hours.

8 0
2 years ago
Read 2 more answers
1. What is greater? 6 pounds and 11 ounces OR 117 ounces? 2. 3/4 tons = how many pounds? (Answer the ones u know!) pls help due
lesya [120]

Answer:

1. Equal. 2. 1500

Step-by-step explanation:

6 x 16 = 96 + 11= 117

3/4 x 2000 = 1500

4 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
It costs 4 tokens to park in a garage for an hour. how many hours can you park with 30 tokens?
babunello [35]

Read the question carefully: it costs 4 tokens to park in a garage for an hour.

We will apply the unitary method to solve this question

It costs 4 tokens to park in a garage for 1 hour

Find how many hours can park in a garage for 1 token

If it costs 4 token to park in a garage for 1 hour

Then it will cost 1 token to park in a garage for 1/4 hour

Step2:

With 20 token we can park in a garage for (1/4) * 20

= 5 hours

So, we can park for 5 hours with 20 tokens.

Another method

If we take twenty tokens and divide them into groups of four, we will find that we are left with five groups of tokens. Each group of tokens represents an hour of parking time. This will give us five groups, or five hours, total.

So, we can park for 5 hours with 20 tokens
5 0
3 years ago
Read 2 more answers
Dan can run 1000 meters in 5 minutes how many can he run in 2 minutes
Rudik [331]

Answer:

800 m

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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