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const2013 [10]
3 years ago
6

Divide 1/2 divide by 1/8

Mathematics
1 answer:
horsena [70]3 years ago
3 0
1/2 is 0.5 and 1/8 is 0.125 so, 0.5/0.125=4 or do the keep, change, flip process... 1/2 times 8/1 which still gets you 8/2 which is then 4
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x1= -5 x2=0.5 y= -5

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Step-by-step explanation:

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Find the common ratio of the sequence 90, 60, 40, 80/3<br> What is the common ratio?
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Answer:

2/3

Step-by-step explanation:

  • <em>Common ratio = next term/previous term</em>

<u>Sequence:</u>

  • 90, 60, 40, 80/3

<u>Common ratio:</u>

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What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​
LenKa [72]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Average \:  cost  \: of  \: 7  \: articles -  >  \\  \frac{(3 \times 30k) + (12 .5k \times 4)}{7}  \\  \frac{90k + 50k}{7}  \\  \frac{140k}{7}  \\  \blue {Average \:  cost  \: of  \: 7  \: articles -  >} \\ 20k

5 0
3 years ago
Prove 2(2x+4)= 16 2(2x) by using the laws of exponents.<br> boris9
storchak [24]

The prove that the equation can be verified using the laws of exponents.

<h3>What is the proof of the equation given; 2^(2x+4)= 16 × 2^(2x)?</h3>

It follows from the task content that the equation given is; 2^(2x+4)= 16 • 2^(2x).

It follows from the laws of indices ; particularly, the product of same base numbers.

The evaluation is therefore as follows;

2^(2x+4)= 16 • 2^(2x)

2^(2x) • 2⁴ = 16 • 2^(2x)

2^(2x) • 16 = 16 • 2^(2x)

Hence, since LHS = RHS, it follows that the expression is mathematically correct.

Read more on laws of exponents;

brainly.com/question/847241

#SPJ1

7 0
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