Answer:
1. 44 + 3x
2. 2y - 8
3. x - 6
15.
16.
17.
Step-by-step explanation:
1. 7² + 2² - 5 - 4 + 3x
49 + 4 - 5 - 4 + 3x
53 - 5 - 4 + 3x
48 - 4 + 3x
44 + 3x
2. - y - 5 + y + 2(2y-y) - 3
-y - 5 + y + 4y - 2y -3
-y - 5 + 5y - 2y - 3
4y - 2y - 5 - 3
2y - 8
3. 5x -3 - x - 3(x + 1²)
5x - 3 - x - 3x - 3
4x - 3x - 3 -3
x - 3 -3
x - 6
15.
=
=
= →
16.
=
=
= →
→
17.
=
=
= →
Hope this helps.
Answer:
or y = 0.25x + 0.5
Step-by-step explanation:
You need to try change the subject from x to y.
x = 4y - 2
We first move -2 to the left, making the equation
x + 2 = 4y i.e.
4y = x + 2
We then divide both sides by 4.
or y = 0.25x + 0.5
We now have successfully made y the subject, and effectively solving the equation.
Answer:
99% confidence interval for the population mean is [19.891 , 24.909].
Step-by-step explanation:
We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.
Assuming the population has a normal distribution.
Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;
P.Q. = ~
where, = sample mean age of selected students = 22.4 years
s = sample standard deviation = 3.8 years
n = sample of students = 19
= population mean
<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>
So, 99% confidence interval for the population mean, is ;
P(-2.878 < < 2.878) = 0.99 {As the critical value of t at 18 degree of
freedom are -2.878 & 2.878 with P = 0.5%}
P(-2.878 < < 2.878) = 0.99
P( <
<
) = 0.99
P( <
<
) = 0.99
<u>99% confidence interval for</u> = [
,
]
= [ ,
]
= [19.891 , 24.909]
Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].