1. You must subtract both sides by 1/4n to end up with 2/4n-18=-4
2.Then you add 18 to both sides to end up with 2/4n=14
3. Now you multiply both sides by 2/4 , aka 1/2 to get n by itself, and you will end up with n=7
n=7 is your answer!
Hello,
if the question is to solve the equation:
1) log must exist:
a)==>2r²-27>0==>(r-√(27/2))(r+√(27/2))==> outside the roots
r<-√(27/2) or r>√(27/2)
b)==>3r²+12r>0 ==>3r(r+4)>0 ==>outside the roots
r>0 or r<-4
==>r<-4 or r>√(27/2)=3.6742...
If this is realized:
2r-27=3r²+12r
==>r²+12r+27=0
Δ=12²-4*27=36=6²
r=(-12+6)/2=-3 or r=(-12-6)/2=-9
One solution r=-9
Proof
Two times four
Eight divide in half
Eight
Six times four
Twenty four
Eight plus twenty four
Thirty two
When you have a triangle just multiply the sides then divide that total by half that will be the area for that
What is the area of the triangular base?
8 square feet
What is the length of edge DF?
4 feet
Answer:
It would be the third one hope i helped
Step-by-step explanation: