The standard deviation for a set of data is 8.5. The mean is 215.

Find the product of the solutions of this equation 2x^2+26x+156=0

NARA [144]

Check the attached file for the answer.

7 0

3 years ago

5 times 7/8 then converted to simplest form?

pantera1 [17]

5*7/8 = 4 3/8
5/1 * 7/8 = 35/8
convert into mixed number because numerator is bigger than the denominator so it it
4 3/8

7 0

2 years ago

Which is a solution to the equation y=2x-5?

erma4kov [3.2K]

Answer:

C. (1, -3)

Step-by-step explanation:

Plug in the x to get the y in the equation. The point must fit the formula.

Plug in C. (1, -3), in which x = 1, y = -3:

(-3) = 2(1) - 5

Simplify:

(-3) = 2(1) - 5

-3 = 2 - 5

-3 = -3 (True).

C is your answer.

~

7 0

3 years ago

Read 2 more answers

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

= 2.5196 $\times 10^{-6}$ .

7 0

3 years ago

Kate and kelvin played a shooting game. Kevin got 52 points which was 54 points less than 2 times that of kates points. How many

Hunter-Best [27]

Answer: 53 points

Step-by-step explanation:

Let the number of points gotten by Kate be represented by x.

Since we are given the information that Kevin got 52 points which was 54 points less than 2 times that of kates points. This can be formed into an equation as:

(2 × x) - 54 = 52

2x - 54 = 52

2x = 52 + 54

2x = 106

x = 106/2

x = 53

Kate got 53 points

4 0

2 years ago