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2 years ago

PLEASE ANSWER I REALLY NEED HELP ON THIS TEST

Mathematics

1 answer:

marshall27 [118]2 years ago

6 0

Answer:

Step-by-step explanation:

beacause if you try to multiple 4x7.5 divided by 2 try it

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Which equation represents a line that passes through (-9, -3) and has a slope of -6?

eimsori [14]

Answer:

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = - 6 and (a, b) = (- 9, - 3), so

y - (- 3) = - 6(x - (- 9)), that is

y + 3 = - 6(x + 9)

8 0

2 years ago

Read 2 more answers

Simplify the expression -9+7

xenn [34]

We have

-9 + 7 = -2

You can also rewrite this as

7 - 9 = -2

If it makes you more comfortable.

Hope this helps.

7 0

3 years ago

Read 2 more answers

The student council raised $150 during the school dance if they charge $3per ticket and received $24 in other donations what is

IRINA_888 [86]

3t + 24 = 150 this is the answer

3 0

2 years ago

Please help me with this probability question.

Vikki [24]

Answer:

1.6 please correct me if im wrong by commenting

Step-by-step explanation:

6 0

3 years ago

Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as the sum, difference

kicyunya [14]

Answer:

$\\ ln(x^2) - ln(x^2 + 1)$ .

For values of x>0, it can be rewritten as $\\ 2ln(x) - ln(x^2 + 1).$

Step-by-step explanation:

For the expression:

$\\ ln(\frac{x^2}{x^2 + 1})$

We can apply this logarithmical property: $\\ ln(\frac{x}{y}) = ln(x) - ln(y).$

Then,

$\\ \frac{x^2}{x^2 + 1} = ln(x^2) - ln(x^2 + 1).$

If we assume values of <em>x </em>> 0 (non negative values for x), then the expression could be rewritten as follows:

$\\ \frac{x^2}{x^2 + 1} = ln(x^2) - ln(x^2 + 1) = 2 ln(x) - ln(x^2 + 1)$ , since $\\ ln(x^{n}) = n*ln(x).$

We have to remember that <em>domain</em> (all possible values x) for logarithmic function is for all x > 0, or mathematically expressed as:

Domain: $\\ {x | x \in R, x > 0}$

8 0

2 years ago