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3 years ago

On a ruler what is the space before one

Mathematics

2 answers:

9966 [12]3 years ago

4 0

It is the 0 to 1 mark

il63 [147K]3 years ago

4 0

Centimeters (2.54cm in an inch) is before 1inch

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What is up guys!

melisa1 [442]

Answer:

Yes, No, Yes

Step-by-step explanation:

Use the Pythagorean theorem:

a² + b² = c²

Verify this for each line:

28² + 45² = 53²
2809 = 2809
Yes

33² + 56² = 64²
4225 ≠ 4096
No

36² + 77² = 85²
7225 = 7225
Yes

5 0

3 years ago

I need help on this one.

Flura [38]

Answer:

1) 180 is a straight line, so 180 - 118 = 62

2) 180 degrees are in a triangle, so 180 - (62) - 73 = 45

3) 180 is a straight line, so 180 - 73 = 107. There are 180 degrees in a triangle, so 180 - 49 - 45 = 86

4 0

3 years ago

Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of succes

lys-0071 [83]

Answer:

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 680 trials

r = number of success

p = probability of success which in our question is 0.55

So, it means X ~ $Binom(n=680, p=0.55)$

Now, we have to find the mean and standard deviation of the given binomial distribution.

Mean of Binomial Distribution is given by;

E(X) = n $\times$ p

So, E(X) = 680 $\times$ 0.55 = 374

Standard deviation of Binomial Distribution is given by;

S.D.(X) = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{680 \times 0.55 \times (1-0.55)}$

= $\sqrt{680 \times 0.55 \times 0.45}$ = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

3 0

4 years ago

Find the equation of the linear function represented by the table below in slope-

mylen [45]

Answer:

1y157

Step-by-step explanation:

7 0

3 years ago

Birth and death rates of animal populations typically are not constant; instead, they vary periodically with the passage of seas

Dominik [7]

Answer:

We readily separate the variables and integrate:

∫dP/P=∫(k+bcos2 $\pi$ t)dt

ln P=kt+(b/2 $\pi$ )*sin2 $\pi$ t+ln C

Clearly C = Po, so we find that P(t) = Poexp(kt + (b/2 $\pi$ )* sin 2 $\pi$ t). The 271- curve with the typical numerical values P_o = 100, k = 0.03, and b = 0.06. It oscillates about the curve which represents natural growth with P_o and k = 0.03. We see that the two agree at the end of each full year.

note:

find the attached graph

8 0

3 years ago