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lubasha [3.4K]
1 year ago
7

2. The alkalinity of a fluid (pH) can be modeled in terms of its hydrogen ion concentration (H+, measured in moles/liter) of the

fluid using the model shown below:pH = - log(H^+)A lab technician finds that a sample of fluid has a pH of 4.5. What is the hydrogen ion concentration of the fluid?

Mathematics
1 answer:
nataly862011 [7]1 year ago
4 0

Given the equation:

pH=-log\mleft(H^+\mright)

You know that a lab technician finds that a sample of fluid has this pH:

pH=4.5

Then, in order to find the hydrogen ion concentration of the fluid, you need to follow these steps:

1. Substitute the pH given in the exercise into the equation:

4.5=-log(H^+)

Multiply both sides by -1:

-4.5=\log (H^+)

2. Solve for:

H^+

Remember that, by definition:

\log _b\mleft(c\mright)=a\Rightarrow b^a=c

In this case, you can identify that:

\begin{gathered} a=-4.5 \\ b=10 \\ c=H^+ \end{gathered}

Hence, substituting values and simplifying, you get:

\begin{gathered} b^a=c \\ 10^{-4.5}=H^+ \\ H^+=0.00003162278\text{ }\frac{moles}{liter} \end{gathered}

Therefore, the answer is:

H^+=0.00003162278\text{ }\frac{moles}{liter}

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3 years ago
The polar coordinates of a point are 3π 4 and 7.00 m. What are its Cartesian coordinates (in m)? (x, y) = 6.06,−3.5 m
Keith_Richards [23]

Answer:

a) \left(x,y\right)=\left(4.95,-4.95\right)

b) r\angle\theta = 7\angle0.5236\,\text{radians}

Step-by-step explanation:

Polar coordinates are represented as: r\angle\theta, where 'r' is the length (or magnitude) of the line, and '\theta' is the angle measured from the positive x-axis.

in our case:

7\angle\dfrac{3\pi}{4}

to covert the polar to cartesian:

x = r\cos{\theta}

y = r\sin{\theta}

we can plug in our values:

x = 7\cos{\dfrac{3\pi}{4}} = -7\dfrac{\sqrt{2}}{2}

y = 7\sin{\dfrac{3\pi}{4}} = 7\dfrac{\sqrt{2}}{2}

the Cartesian coordinates are:

\left(x,y\right)=\left(-7\dfrac{\sqrt{2}}{2},7\dfrac{\sqrt{2}}{2}\right)

\left(x,y\right)=\left(4.95,-4.95\right)

(b) to convert (x,y) = (6.06,-3.5)

we'll use the pythagoras theorem to find 'r'

r^2 = x^2+y^2

r^2 = (6.06)^2+(-3.5)^2

r = \sqrt{48.97} \approx 7

the angle can be found by:

\tan{\theta} = \dfrac{y}{x}

\tan{\theta} = \dfrac{3.5}{6.06}

\theta = \arctan{left(\dfrac{3.5}{6.06}\right)}

\theta = 0.5236 \text{radians}

to convert radians to degrees:

\theta = 0.5236 \times \dfrac{180}{\pi} \approx 30^\circ

writing in polar coordinates:

r\angle\theta = 7\angle30^\circ\,\,\text{OR}\,\,7\angle0.5236\,\text{radians}

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