If two tangent segments to a circle share a
common endpoint outside a circle, then the two segments are congruent. This
is according to the intersection of two tangent theorem. The theorem states
that given a circle, if X is any point
within outside the circle and if Y and Z are points such that XY and XZ are
tangents to the circle, then XY is equal to XZ.
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Answer:
4x+7
Step-by-step explanation:
X+2y = 9 ---------eq.1
x-y =6 ----------- eq.2
x = 9 -2y (from eq. 1)
Now substitute the value of x in the second eq.2
9-2y-y =6
-3y = -3
y =1
So,
x +2 (1)= 9
x= 7
Answer:
there are no real solutions
Step-by-step explanation:

there is a rule that says

so we have

and we have the definition

so we have

and using the quadratic formula we get that
there are no real solutions
Step-by-step explanation:
b²+7b+10
Common factors are 5,2
b²+7b+10
b²+2b+5b+10
b(b+2)+5(b+2)
(b+2)(b+5)
Hope it helps.✨✨