If two tangent segments to a circle share a common endpoint outside a circle, then the two segments are

1 answer:

4 0

If two tangent segments to a circle share a common endpoint outside a circle, then the two segments are congruent. This is according to the intersection of two tangent theorem. The theorem states that given a circle, if X is any point within outside the circle and if Y and Z are points such that XY and XZ are tangents to the circle, then XY is equal to XZ.

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2 years ago

a certain virus infects one in every 600 people. a test used to detect the virus in a person is positive 90% of the time if the

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the probability that a person has the virus given that they have tested positive is 0.0151.
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P(A) = 1/600 = 0.0017

P(B) = 0.9 * 0.0017 + 0.1 * (1 - 0.0017) = 0.1014

A) P (has the virus | tested positive) = P (tested positive | has the virus) ×

P (has the virus)/ P (tested positive)

= 0.9 × 0.0017/0.1014

= 0.0151

B) P (does not have the virus | tested negative) = P (tested negative | does not have the virus) × P (does not have the virus)/ P (tested negative)

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Probability is the department of mathematics regarding numerical descriptions of ways likely an occasion is to occur, or how possibly it's far that a proposition is genuine. The possibility of an occasion varies between zero and 1, wherein, roughly speaking, 0 suggests the impossibility of the occasion and 1 shows certainty. The better the possibility of an event, the more likely it is that the event will arise.

A simple instance is the tossing of an honest (unbiased) coin. since the coin is truthful, the 2 results ("heads" and "tails") are both equally likely; the possibility of "heads" equals the chance of "tails"; and considering the fact that no different results are feasible, the possibility of both "heads" or "tails" is 1/2 (that could additionally be written as 0.5 or 50%).

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1 year ago

Pls help! I don’t understand bc I’m not smart-

Ipatiy [6.2K]

Answer:

78.5 m²

Step-by-step explanation:

The formula to find the area of a quarter of a circle: $\frac{1}{4} * \pi * r^{2}$ , where $r$ is the radius (diameter ÷ 2) and the $\pi$ is alterable.