Which choices will complete the reasoning for statement #3?

Plz help advanced calculus

love history [14]

Answer:

I wanna say that its K. Sin 2x

If i'm wrong i'm so sorry

Hope i helped you in some way

6 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

3 years ago

Anyone know how to find the area of an equilateral triangle circumscribed about a circle, given the radius of the circle?

tia_tia [17]

Warning: This might be rough...
First draw it out. Label the angles at the corners of the triangle 60 (definition of equilateral triangles). Now draw a line from the center of the circle to the corner, splitting the corner in half. Label this line R and a corner as 30 degrees. No to find the height of this triangle, you do rsin(30). The base of this triangle is 2rcos(30). Now find the area of this mini triangle (rsin(30)*2rcos(30)/2=r/2*rsqrt(3)/2=r^2sqrt(3)/4). Now multiply this by 3 because you have 3 mini triangles... to get...
<span>r^2 3sqrt(3)/4</span>

8 0

3 years ago

what is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? (1 point) y − 5

makkiz [27]

According to the question, the line is through the points $(0,5)$ and $(-2,11)$

To calculate the slope using standard formula that is :

$m = \frac{(y(2)-y(1))}{(x(2)-x(1))} = \frac{(11-5)}{(-2-0)} =\frac{6}{-2} = -3$

Now the slope equation will be: $m(x(2)-x(1)) = (y(2)-y(1))$

$y-5 =(-3)(x-0) = y = -3(x)+5$

The slope-intercept form is: $y = -3x+5$

What is the equation of the line?

To represent the set of points in an algebraic form is known as the equation of line. The set of points represent lines in the coordinate system. The parameters can be calculated and those parameters are slope and y-intercept.

To learn more about the equation of the line from the given link:

<u>brainly.com/question/14037984</u>

#SPJ4

5 0

1 year ago

What is 3x+70=8x-20 show work

Elena-2011 [213]

Answer:

Hi there!

Your answer is:

x= 18

Step-by-step explanation:

3x+70=8x-20

Isolate x on left side

3x+70=8x-20

-8x -8x

-5x +70 = -20

Isolate whole numbers on right side

-5x +70 = -20

-70 -70

-5x = -90

Isolate x by dividing both sides by -5

-5x = -90

/-5

x= 18

6 0

3 years ago