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Anni [7]
3 years ago
5

Anyone know this? Please help it'd mean a lot

Mathematics
1 answer:
monitta3 years ago
4 0
I'm guessing it's $20.16

If you divide 336 by 100, you get 3.36, which gives you 336 if you multiply it by 100.

Since you multiply 100 by 3.36 to get to 336, you have to do that to 6 to get the total amount of sales.

6 x 3.36 = $20.16
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Find all x-intercepts of the function. Express your answer as a list of x-values.
-Dominant- [34]

Answer:

all x intercepts [-4, 0] [4, 0]

Step-by-step explanation:

x-intercept, i.e. y=0

f(x) = x^3 - 4x^2 - 16x + 64 = 0

(x^3 + 4^3) - 4x^2 - 16x = 0         [FYI, x^3 + y^3 = (x + y)(x^2 - xy + y^2)]

(x + 4)(x^2 - 4x + 16) - 4x^2 - 16x = 0

(x + 4)(x^2 - 4x + 16) - 4x(x + 4) = 0

(x + 4)(x^2 - 4x + 16 - 4x) = 0

(x + 4)(x^2 - 8x + 16) = 0

(x + 4)(x - 4)^2 = 0

x = -4 or 4

all x intercepts [-4, 0] [4, 0]

4 0
2 years ago
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The graph of the function f(x) = (x + 2)(x + 6) is shown below. Which statement about the function is true? The function is posi
11111nata11111 [884]
The critical values for x are -2 and -6.
We break the function domain into regions:
-∞ to -6 f(x) ≥ 0
-6 to-2 f(x) < 0 this is the correct statement, answer 2
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8 0
3 years ago
Find the value for P in the formula P=I/RT when I = 48, R = 2, and T = 6.
frosja888 [35]
According to the formula...
P= 48/ 2x6
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5 0
3 years ago
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(X^4)-(45x^2)+324 what are the zeroes? And how many turning points?
dmitriy555 [2]

Zeroes:

We must solve

x^4-45x^2+324=0

To do so, we define the auxiliary variable t=x^2. The equation becomes

t^2-45t+324=0

The quadratic formula yields the solutions

t=9,\quad t=36

Substituting back t=x^2 gives

x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x

If we set the derivative to be zero, we have

4x^3-90x=0 \iff x(4x^2-90)=0

So, the derivative is zero if x=0 or

4x^2=90 \iff 2x^2=45 \iff x^2=\dfrac{45}{2}\iff x=\pm\sqrt{\dfrac{45}{2}}

6 0
3 years ago
What is the volume of a cube that has a height of ten inches
Zielflug [23.3K]

Answer:

1000 cubic inches

Step-by-step explanation:

(10)(10)(10) = 1000

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3 years ago
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