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Westkost [7]
3 years ago
6

Alex wrote 103.903 in expanded form as 100+3x1+9x1/100+3x1/1,000 explain his mistake and how to correct it

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0
The 9 is in the tenths place so it should be 9x1/10. Meaning it would be 100+3x1+9x1/10+3x1,000
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there are 34 hats at shop.there are 2 times as many scarves as hats at the shop. How many scarves are at the shop?
schepotkina [342]
34 x 2 = 68

Or

34 + 34 = 68
3 0
3 years ago
Read 2 more answers
I reached into my pocket and found that I have only dimes n nickels. I have 2.00. I have 11 coins. How many dimes do I have?
sdas [7]
This is not possible,  because if you had 11 coins,  then not even 11 dimes will cover it,  because 11*10 is 110,  or $1.10
6 0
3 years ago
F(x)= -(x+7)²+4. Which of the following is true for f(x). Check all that apply
3241004551 [841]
A and D seem to be the only correct ones. Hope this helps

4 0
3 years ago
Components of a certain type are shipped to a supplier in batches of ten. Suppose that 50% of all such batches contain no defect
ad-work [718]

Answer:

a) P (0 defective component) = 0.5

   P( 1 defective component ) = 0.35

    P( 2 defective component ) = 0.15

b) P( 0 ) = 0

   p ( 1 ) =  1

   p ( 2 ) = 0.33

Step-by-step explanation:

p( no defective ) = 0.5

p( 1 is defective ) = 0.35

p( 2 is defective ) = 0.15

Given that 2 components are selected at random

<u>a) Given that neither component is defective </u>

Probability of 0 defective component = 0.5

P( 1 defective component ) = 0.35

P( 2 defective component ) = 0.15

<u>b) Given that one of the two tested component is defective </u>

P( 0 defective ) = 0

P( 1 defective ) = P ( \frac{x=1}{x\geq 1} ) = p( x = 1 ) / 1 - P ( x = 0 )

                                        = ( 0.5 )^1 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^1

                                        = 0.5 * 1 / 1 - 0.5 = 0.5 / 0.5 =  1

p ( 2 defective ) = p( x = 3 ) / 1 - P ( x = 0 )

                         = ( 0.5 )^2 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^2

                         = 0.25 / 0.75 = 0.33

<u />

5 0
3 years ago
Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.
NemiM [27]

Complete question is;

Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.

1) 2x + y = 10

x - 3y = -2

2) x + 2y = 5

2x + y = 4

3) x + 3y = 5

6x - y = 11

4) 2x + y = 10

-6x - 3y = -2

Answer:

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

Step-by-step explanation:

1) 2x + y = 10 - - - (eq 1)

x - 3y = -2 - - - (eq 2)

Multiply eq 1 by 3 to get;

6x + 3y = 30

Add it to eq 2 to get;

7x = 28

x = 28/7

x = 4

2) x + 2y = 5 - - - (eq 1)

2x + y = 4 - - - (eq 2)

Multiply eq 2 by 2 to get;

4x + 2y = 8

Subtract eq 1 from it to get;

3x = 3

x = 3/3

x = 1

3) x + 3y = 5 - - - (eq 1)

6x - y = 11 - - - (eq 2)

Multiply eq 2 by 3 to get;

18x - 3y = 33

Add to eq(1) to get;

19x = 38

x = 38/19

x = 2

4) 2x + y = 10 - - - (eq 1)

-6x - 3y = -2 - - - (eq 2)

Make y the subject in eq 1 to get;

y = 10 - 2x

Put in eq (2);

-6x - 3(10 - 2x) = -2

-6x - 30 + 6x = -2

0 = 0

Thus,no solution exists.

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

3 0
3 years ago
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